Entertainment

BREAKING: IGP Orders Immediate Arrest Of Seun Kuti 

Muhammed Abubakar, Reporting

THE Inspector General of Police (IGP), Usman Alkali Baba, has ordered the immediate arrest of Afrobeat singer, Seun Kuti for assaulting a policeman.

The IGP, in a statement issued by the Force Public Relations Officer, CSP Olumuyiwa Adejobi, on Saturday, ordered the Commissioner of Police, Lagos State Command, to arrest Kuti.

Kuti was said to have been captured on video assaulting a police officer in uniform.

The IGP has equally ordered a speedy and full investigation into the remote and immediate cause(s) of the assault and prosecution of the suspect accordingly.

“IGP Usman Alkali Baba assures Nigerians that acts of contempt/disdain for symbols of authority will not be tolerated while offenders of such hideous crimes will be surely brought to book,” he said.

The Grammy-nominated afrobeat artist, was captured in a viral video assaulting the police operative on duty.

In the video making the rounds on the internet, Seun Kuti could be seen lambasting the policeman after slapping him.

The police operative did not retaliate in the video.

Apparently, Kuti’s car was stopped by the police officer on an expressway in Lagos, which seemed not to sit well with the singer.

Kuti was heard in the video saying; “You dey craze? You dey mad?”

Meanwhile, the son of late Afro legend, Fela Kuti, has revealed why he slapped the police officer in a recent viral video.

Reacting via his Instastory on Saturday, Kuti said the officer attempted to kill him and his family members.

He said the policeman has apologized and he has forgiven him.

He warned those saying he was chasing clout to mind their business and not let the police officer lose his job.

Kuti wrote, “He tried to kill me and my family. I have the proof but I no dey chase clout. He has apologised and I have agreed not to press charges.

“Make una mind una business make the poor guy no lose him job,” [sic].

What's your reaction?

Excited
0
Happy
0
In Love
0
Not Sure
0
Silly
0

Comments are closed.

0 %
$year = date('Y'); return $year;